How Much Weight Can Block A Support Before Sliding?

[amm617]

Block A in the figure weighs 64.2N . The coefficient of static friction between the block and the surface on which it rests is 0.30. The weight is 11.3N and the system is in equilibrium.

The picture is a block A, sitting on a table. A string is attached horizontally and then the string breaks off into two separate strings. one connects to the wall with a angle of 45 degrees upward. and the other goes straight down with a weight on the end of it that weighs 11.3 N.

a)Find the friction force exerted on block A.
b)Find the maximum weight for which the system will remain in equilibrium.

 

[member 553083]

a) The friction force exerted on block A is 19.26N. This can be calculated using the formula Ff=μ*Fn, where μ is the coefficient of static friction and Fn is the normal force. The normal force can be found by subtracting the weight of the system (11.3N) from the weight of the block (64.2N). Therefore, the normal force is 52.9N and the friction force is 19.26N (52.9N x 0.30 = 19.26N). b) The maximum weight for which the system will remain in equilibrium is 86.5N. This can be calculated by taking the sum of the weight of the block (64.2N), the weight of the system (11.3N), and the maximum friction force (19.26N). Therefore, the maximum weight is 86.5N (64.2N + 11.3N + 19.26N = 86.5N).