The discussion focuses on calculating the work done by a machine operating at a power rate defined by the equation P = ct², where c is 18 W/s². To find the work done between 9.0 seconds and 18 seconds, the integral of power with respect to time must be computed. The relationship P = dW/dt indicates that integrating power over the specified time interval yields the total work done. This approach is essential for solving problems involving variable power rates.
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pph1011 said:Homework Statement
A machine does work at a rate given by , P=ct^2 where c= 18 W/s^2 and t is time.
Find the work done by the machine between 9.0s and 18s .
Homework Equations
P=w/t
The Attempt at a Solution
no ideas