How Much Work Is Done by an Olympic Triathlete Accelerating on Her Bicycle?

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SUMMARY

The discussion centers on calculating the work done by an Olympic triathlete accelerating from 5 m/s to 10 m/s on her bicycle, with a combined mass of 105 kg. The kinetic energy (Ek) is calculated using the formula Ek = 1/2mv^2. The user attempts to find the change in kinetic energy to determine the work done, arriving at a value of 3937.5 joules, which is confirmed as correct through proper application of the equations.

PREREQUISITES
  • Understanding of kinetic energy calculations using Ek = 1/2mv^2
  • Familiarity with the concept of work as the change in energy
  • Basic knowledge of physics principles related to motion and acceleration
  • Ability to manipulate and solve algebraic equations
NEXT STEPS
  • Review the principles of energy conservation in physics
  • Explore advanced applications of kinetic energy in sports science
  • Learn about the relationship between force, mass, and acceleration using Newton's second law
  • Investigate the impact of aerodynamic factors on cycling performance
USEFUL FOR

Students studying physics, sports scientists, coaches, and anyone interested in the mechanics of athletic performance and energy expenditure in cycling.

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Homework Statement


How much work is done by an Olympic triathlete who accelerates herself on her bicycle (combined mass of 105kg) from 5 m/s to 10 m/s?


Homework Equations


Ek = 1/2mv^2
W = Fapp(d)


The Attempt at a Solution


Ek = 1/2m[(5 + 10)/2]^2

how do i go about solving this?
 
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Work is the change in energy of an object. So how much did she start with, and how much did she end up with.
 
Is the answer 3937.5 joules?
 

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