How powerful should the magnet be to repel against gravity?

AI Thread Summary
To repel a magnet against gravity, the magnetic force must exceed the gravitational force acting on it. This gravitational force can be calculated using Newton's law, where the force equals the product of the gravitational constant, the mass of the Earth, and the mass of the magnet, divided by the square of the distance from the Earth's center. The magnetic force can be expressed as F = I Δl B sin θ, where I is current, Δl is the length of the conductor, B is the magnetic field strength, and θ is the angle between the field and the current. Essentially, the magnetic field strength needs to be sufficiently powerful to counteract the gravitational pull. Understanding these forces is crucial for achieving the desired repulsion.
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i have two magnets and i want to repel one magnet against gravitational force upwards..so how powerful the magnet should be?i can calculate the gravitational force using Newton's law f=gm1m2/r2 where m1 is mass of Earth and m2 is mass of one magnet...so the magnetic force should be greater than this force ...help me...
 
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You require the force on the magnet to be equal to the force of gravity, as you said.

F = I \Delta l B sin \theta = \frac{Gm_{1}m_{2}}{r^{2}}
 
spidey said:
i have two magnets and i want to repel one magnet against gravitational force upwards..so how powerful the magnet should be?i can calculate the gravitational force using Newton's law f=gm1m2/r2 where m1 is mass of Earth and m2 is mass of one magnet...so the magnetic force should be greater than this force ...help me...

Hi spidey! :smile:

Technically, it's Gm1m2/r2,

but we can write Gm1/r2 = g, the usual gravitational constant at the Earth's surface,

so f = Gm1m2/r2 = m2g. :smile:
 
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