How pressure is measured using a manometer

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SUMMARY

This discussion focuses on the principles of pressure measurement using a manometer, specifically addressing why points at the same height in a liquid exhibit equal pressure. The explanation is rooted in Bernoulli's equation and the concept of forces acting on a fluid element. The equilibrium condition of the liquid, influenced by air pressure and water pressure, leads to the conclusion that pressure varies with depth, not height, due to the weight of the liquid above.

PREREQUISITES
  • Understanding of Bernoulli's equation
  • Basic knowledge of fluid mechanics
  • Familiarity with pressure concepts in physics
  • Ability to interpret free-body diagrams
NEXT STEPS
  • Study Bernoulli's equation in detail
  • Learn about hydrostatic pressure and its applications
  • Explore free-body diagram techniques for fluid analysis
  • Investigate various types of manometers and their uses
USEFUL FOR

Physics students, engineers, and anyone interested in fluid dynamics and pressure measurement techniques will benefit from this discussion.

sluo
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Hello. I'm reading a physics book on my own and am learning about pressure measurements. I have a question with how pressure is measured using a manometer. Here is a link talking about it:

http://www.upscale.utoronto.ca/PVB/Harrison/Manometer/Manometer.html

My question is, why do points at the same height necessarily have the same pressure (as in Cases 2 and 3)? If the liquid is in equilibrium, why can't we say that the pressure at any point in the liquid is equal to the pressure at any other point?

Thanks!
 
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sluo said:
Hello. I'm reading a physics book on my own and am learning about pressure measurements. I have a question with how pressure is measured using a manometer. Here is a link talking about it:

http://www.upscale.utoronto.ca/PVB/Harrison/Manometer/Manometer.html

My question is, why do points at the same height necessarily have the same pressure (as in Cases 2 and 3)? If the liquid is in equilibrium, why can't we say that the pressure at any point in the liquid is equal to the pressure at any other point?

Thanks!
It can be explained by thinking about forces and free-body diagrams.

From your link:
Fig2.png
Consider the water lying between the dashed lines on the right. It has three forces acting on it:

1. Force due to air pressure at A, acting downward
2. Force due to water pressure at B, acting upward
3. Weight, acting downward

Since this water does not move, it must have zero net force acting on it. Because there is a gravitational force acting on it, the pressures at A and B cannot be equal.
 

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