How Quickly Does a Spring's Restoring Force Counteract Applied Force?

  • Thread starter Thread starter chandran
  • Start date Start date
  • Tags Tags
    Mass Spring
Click For Summary
SUMMARY

The discussion centers on the interaction between an applied force and a spring's restoring force as described by Newton's second law. When a force \( f \) is applied to a mass \( m_1 \) attached to a spring, the mass initially accelerates according to \( a = f/m_1 \). However, the spring's restoring force counteracts this acceleration, affecting the net force acting on the mass. The time delay in the spring's response to the applied force results in the mass potentially achieving a higher acceleration before the restoring force fully engages, illustrating the principles of conservation of energy and momentum.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Basic knowledge of spring mechanics and Hooke's Law
  • Familiarity with concepts of potential energy and kinetic energy
  • Awareness of conservation of momentum principles
NEXT STEPS
  • Study the dynamics of oscillating systems using differential equations
  • Explore the implications of Hooke's Law in real-world applications
  • Learn about energy transfer in mechanical systems
  • Investigate the effects of damping in spring-mass systems
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in the dynamics of spring systems and force interactions.

chandran
Messages
137
Reaction score
1
Let me start with Newton second law,a mass m acted upon by force f will accelerate to f/m

Let me consider a spring fixed to one end and a mass(call m1) attached to other end.

when i apply a force f to the mass(m1) it shouldl accelerate to a=f/m1 if Newtons law is to be obeyed.

But since the spring has a restoring force the mass doesn't accelerate. But at what time the restoring force comes into picture. Will the spring take some time before it applies a restoring force=applied force. If it takes some time to apply restoring force in that duration the force f must have given the mass m a much higher acceleration and ..... the mass will accelerate. I need some discussion on this ...
 
Physics news on Phys.org
The force you are talking about is not directly applied to the mass, its applied to the spring. The spring will compress to some degree as the force is applied, all depending on how big of a force and how quickly it is applied. The reason the mass could wind up having a higher accelleration is because the force was applied for some length of time into the spring. The spring compresses, potential energy. In the end the conservation of energy and momentum will be shown.
 
chandran said:
when i apply a force f to the mass(m1) it shouldl accelerate to a=f/m1 if Newtons law is to be obeyed.
Realize that it is the net force on the mass that determines the acceleration; the net force will be the combination of applied force and the spring's restoring force. The restoring force acts whenever the mass is displaced from equilibrium.
 

Similar threads

  • · Replies 56 ·
2
Replies
56
Views
5K
Replies
17
Views
2K
Replies
29
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
1
Views
1K
Replies
16
Views
3K