The discussion centers on calculating the probability P(X < 1.23) using the moment generating function (MGF) m(t) = (1-p+p*e^t)^5. Participants clarify that m(t) is not expressed as e^(tx) * f(x), but rather as the integral ∫{e^(tx) f(x) dx: x=0..∞}. It is emphasized that using a normal table is inappropriate due to the distribution's deviation from normality, and instead, one should expand the power series of the MGF to determine the distribution explicitly.
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psycho007 said:given m(t) = (1-p+p*e^t)^5
what is probability P(x<1.23)
i know that m(t) = e^tx * f(x)
m'(0) = E(X)
and m''(0) , can find the var(x)
should i calculate it using a normal table?