How Strong is the Electric Field Across a Cell Membrane?

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 9K views
Boozehound
Messages
29
Reaction score
0
The inner and outer surfaces of a cell membrane carry a negative and positive charge, respectively. Because of these charges, a potential difference of about 0.0730 V exists across the membrane. The thickness of the membrane is 8.22E-9 m. What is the magnitude of the electric field in the membrane?

so i took .0730V and multiplied it by 1.60E-19C to get an answer in joules. i ended up getting 1.168E-20J. i then took that and divided it by .0730V to get an answer in coulombs. and i got 1.6E-19C for that. then i took my answers and plugged them into the equation. E=8.99E9(1.6E-19)/(8.22E-9)^2. then the final answer i got was . and i punched it in and it was wrong. i don't know if i am using the wrong formulas. most likely that's the case. so if you see something I am doing wrong and can point me in the right direction that would be a great help. thanks.
 
Physics news on Phys.org
wait, too hard, and I'm thinking youre confused re maybe the notion of a test charge. I think, iirc, you just need to treat this as a ccapacitor which relates E,V, and thickness.