How to Account for Rotational Motion in a Pulley Problem?

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SUMMARY

The discussion focuses on calculating the tension in a pulley system involving two hoops with masses M1 and M2 and radii R1 and R2. The correct formula for tension is established as t = gM1M2/(M1+M2). A common mistake identified is neglecting the rotational motion of the hoops, which leads to an incorrect tension value that is twice the expected result. This scenario is a variation of Atwood's machine, which complicates the analysis due to the different moment arms of the masses.

PREREQUISITES
  • Understanding of rotational dynamics and moment of inertia
  • Familiarity with the principles of Atwood's machine
  • Knowledge of Newton's laws of motion
  • Basic grasp of gravitational forces in physics
NEXT STEPS
  • Study the concept of moment of inertia for different shapes
  • Learn about the dynamics of Atwood's machine variations
  • Explore the effects of rotational motion on tension in pulley systems
  • Investigate the relationship between linear and angular acceleration
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Physics students, educators, and anyone interested in understanding the dynamics of pulley systems and rotational motion in mechanics.

danny271828
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A massless string is placed over a massless pulley, and each end is wound around and fastened to a vertical hoop. The hoops have masses M1 and M2 and radii R1 and R2. The apparatus is placed in a uniform gravitation field g and released with each end of the string aligned along the field.



I have to show that the tension is t = gM1M2/(M1+M2)



I keep getting twice this value.
 
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danny271828 said:

I keep getting twice this value.

You are getting twice of the value, because you are neglecting the rotational motion of the hoops. The answer you got (twice value) is in the case when hoops are pointlike.
 

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