How to Amplify a 2.5 mA Pulse to Drive a Latching Relay?

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To amplify a 2.5 mA pulse for driving a latching relay, using a transistor is recommended, specifically a Darlington transistor like the TIP120, which can handle currents over 50 mA. A diode should be included in the circuit to protect the transistor from high voltage spikes generated by the relay coil. A 10k resistor should be connected from the data input to ground for proper operation. Users are encouraged to consult the transistor's datasheet for detailed specifications. The discussion concludes with a participant confirming they will acquire the necessary components to implement the solution.
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Hey. I am trying to use a single quick pulse of about 2.5 mA to run a latching relay. I know that this signal needs to be amplified (probably with a transistor) but am unfamiliar on how to do this.

Thanks for the help,

John
 
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Here is a relay driver. The diode in this circuit is used to protect the transistor from high voltage that is being induced by the relay coil.


http://www.vlearnvshare.com/home/images/articles/NPN-DRIVER1.GIF
 
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If the relay current is over 50 milliamps, you should use a Darlington transistor, such as the TIP120 (available at Radioshack) or equivalent. See datasheet

http://www.learn-c.com/tip120.pdf

The current gain at saturation is ~250. You should also have a 10k resistor from the data input to ground.

Bob S
 
Thanks for the help. I'm going to get the parts today so I'll let you know.
 
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