How to calc the force needed to change direction of a moving object?

Click For Summary
To calculate the force needed to change the direction of a moving ball, one must consider the ball's mass, velocity, and the desired change in momentum. The formula F=ma is essential, but determining the necessary acceleration requires a clear understanding of the ball's trajectory. The discussion highlights the importance of specifying a coordinate system for direction changes and clarifies that the ball will not stop after traveling a certain distance unless external forces like air resistance are considered. It is emphasized that one cannot "overpower" kinetic energy; instead, the focus should be on changing momentum. Accurate calculations depend on additional information, such as air resistance and the exact path taken during deflection.
Dastan
Messages
3
Reaction score
0

Homework Statement



A ball [Weight 5 kg & velocity 20 m/s] coming straight at me. How much force I would need to change its direction at 0 degree on left side & sent 20 meters?

I simply don't know what formula I should use.Let alone how to calc it.
 
Physics news on Phys.org
How much force I would need to change its direction at 0 degree on left side & sent 20 meters?
How do you mean that? (Can you draw a sketch?)

The answer will certainly use F=ma, but to determine the necessary acceleration you have to determine which path the ball should take.
 
Suppose the ball [Red Dot] is coming from above at said speed at 90 degree.

http://img27.imageshack.us/img27/8700/3e0a.png

I have to use force to send it to green dot [after it reaches me] while it was still moving.

Shouldn't I have to overpower the ball's KE?:hmm
 
Last edited by a moderator:
The "zero degrees" before was misleading because you had not specified a coordinate system. Apparently you are assuming a coordinate system in which 0 degrees is to your left and 90 degrees directly ahead. In other words you want to change its direction by 90 degrees.

But then you say "and sent 20 meters" That makes no sense because you can only change it velocity. Unless you are assuming specific air resistance, which you do not give, there is no reason for it to stop at any distance.
 
In addition, if you deflect the ball like this, the force will depend significantly on the exact path the ball takes during that deflection.
 
Dastan said:
Shouldn't I have to overpower the ball's KE?:hmm
You can't 'overpower' Kinetic Energy; whatever you may mean by it...
You can absorb K.E. You can give it more K.E. Overpower, mmm..nope.
The change in direction of velocity relates to change in momentum.
Force is rate of change of momentum wrt time.
With given information you can at best calculate change in momentum.
Also as others have mentioned the ball won't stop after 20m.
Have you been given air resistance, or the height at which ball is at?
And it may that by 20m you really mean 20m/s?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 1 ·
Replies
1
Views
823
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 62 ·
3
Replies
62
Views
5K
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 15 ·
Replies
15
Views
1K
Replies
13
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K