How to calculate a integral on boundary

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The integral in question, \oint_{\Sigma}f(x,y)g(x,y)\mathbf{n}\cdot d\mathbf{s}, evaluates to zero because g(x,y) is defined as zero on the boundary \Sigma. Since the integrand becomes zero throughout the integration domain, the result of the integral is indeed zero. This conclusion is straightforward given the conditions provided. The discussion emphasizes the importance of understanding the implications of the integrand's value on the outcome of the integral. Thus, the integral equals zero under the specified conditions.
Stole
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Hi,
I would like to calculate the following integration:

\oint_{\Sigma}f(x,y)g(x,y)\mathbf{n}\cdot d\mathbf{s}

where g(x,y)=0 on \Sigma, and \mathbf{n} is the outward pointing unit normal field of the boundary \Sigma.

In this case does the integral equals to 0?

Thanks!
 
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Stole said:
Hi,
I would like to calculate the following integration:

\oint_{\Sigma}f(x,y)g(x,y)\mathbf{n}\cdot d\mathbf{s}

where g(x,y)=0 on\Sigma, and [/itex]\mathbf{n}[/itex] is the outward pointing unit normal field of the boundary \Sigma.

In this case does the integral equals to 0?

Thanks!
You forgot the [ tex ] and [ /tex ] tags!
Yes, if your integrand is always 0, the integral is 0. Isn't that obvious?
 

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