- #1

katkinson

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## Homework Statement

This is an update to an earlier post. Since then, I now understand that a pendulum stops when its tension force= mg sin(theta)--because then centripetal force will=0, so velocity will be 0. However, now I am trying to determine how a trapeze would work on the moon.

## Homework Equations

KE=1/2 mv^2

PE= mgh

T=2π√(L/g)

Fc=mv^2/r

Ft=Fc-mg sin(theta)

KE (initial) + PE (initial) = KE (final) + PE (final)

## The Attempt at a Solution

Drawing a free body diagram, I determined that when an object peaks during its swing the following is true: Because the object is stopped, Fc=0. Because Fc=0 and the radius and mass are supposedly constant, velocity must=0. (That also means that it is 100% PE). Because Ft - mg sin (theta) = 0, then

**Ft= mg sin (theta).**I am trying to determine what sin (theta) is, because then I can determine the length of the swing on the moon. However, I do not know how to determine Ft so I thought I would try using the other method while using T=2π√(L/g). However, I do not know how I can use the time to determine the length of the arc

Thanks so much