How to calculate distance when there's a changing force???D: 1. The problem statement, all variables and given/known data A 3.50kg box is moving to the right with speed 10.0m/s on a horizontal, frictionless surface. At t = 0 a horizontal force is applied to the box. The force is directed to the left and has magnitude F(t) = (6.00N/s^2)t^2 What distance does the box move from its position at before its speed is reduced to zero? If the force continues to be applied, what is the speed of the box at 4.00 ? 2. Relevant equations x = x0 + v0xt + .5axt^2 F = ma vx = v0 + axt I might be missing several 3. The attempt at a solution I don't even know where to start for this problem. I drew a free body diagram and it didn't help me. What I calculated : Force downward is 3.5kg x 9.8 m/s^2 or the weight I don't know how to calculate the forces to the left and right. For the second question I plugged in 4 to the F(t) equation and got 96 so I used 96 = ma SO 96 = 3.5 * a a = 27.4 and I plugged 27.4 into vx = v0x + axt so vx = 10m/s + 27.4(4) and got 119.7 and this is not correct. Help please, thank you!