1. The problem statement, all variables and given/known data A 8.00kg block of ice, released from rest at the top of a 1.04m--long frictionless ramp, slides downhill, reaching a speed of 2.76m/s at the bottom. What is the angle between the ramp and the horizontal? This I calculated as 21.9 degrees What would be the speed of the ice at the bottom if the motion were opposed by a constant friction force of 10.9N parallel to the surface of the ramp? 2. Relevant equations F = ma w = mg vx = v0 + axt i might be missing several 3. The attempt at a solution so I drew a diagram which i probably can't move to here, but-- I aligned the x and y axis to match the normal force and the friction force I calculated the force of the block of ice going down the ramp by using "mgsin(theta)" (where theta is 21.9) and got 29.24 N. I subtracted 10.9N from it to get the net force of 18.34N. I used F = ma to find acceleration and I got 2.293m/s^2. I tried putting in 2.293m/s^2 and it says close but not quite. How do I find t so I can use the vx = v0 + axt??? I got stuck up to there and some(or all of it) may be wrong since physics is my weakest subject haha.