How to Calculate Energy Released in Fission Reaction

[FlipStyle1308]

Homework Statement

1_0_n + 235_92_U 140_54_Xe + 94_38_Sr + 2 1_0_n
Using the above reaction, determine the amount of energy.

Homework Equations

mi = 235.043925u + 1.008665u + 236.05259u
mf = 140.914406u + 93.915356U + 2(1.008665u) = 236.847092Uu
delta m = 0.794502
E = deltam(c^2) = (0.794505u)(931.5MeV/c^2/u)c^2 = 740.078613

The Attempt at a Solution

See above in part . My answer is incorrect. I double checked my work, and I got the same answer. Can anybody figure out what I'm doing wrong? Thanks.

 

[Astronuc]

Compare:

mi = 235.043925u + 1.008665u

m (U-236) = 236.05259u

mf = 140.914406u + 93.915356U + 2(1.008665u)


²³⁵U + n -> ²³⁶U* -> FP + 2n

 

[FlipStyle1308]

Okay, how do I incorporate the middle product into my equation? The book wasn't too good with explaining that part.