How to calculate energy used in a variable speed drive

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SUMMARY

This discussion focuses on calculating energy savings when using a Variable Speed Drive (VSD) for a water pump compared to a traditional AC motor running at full load with a restriction. The key calculation involves determining the energy consumed, represented as the area under the curve of a function that describes unit energy per time. The formula for additional power loss due to restrictions is ΔP * Q, where ΔP is the pressure drop and Q is the flow rate. The experiment aims to demonstrate the cost-effectiveness of VSDs by comparing energy consumption between both methods.

PREREQUISITES
  • Understanding of Variable Speed Drives (VSDs)
  • Knowledge of fluid dynamics, specifically mass flow rates
  • Familiarity with basic electrical engineering concepts related to AC motors
  • Ability to interpret mathematical models related to energy consumption
NEXT STEPS
  • Research the energy efficiency benefits of Variable Speed Drives in industrial applications
  • Learn about fluid dynamics principles, particularly mass flow rate calculations
  • Study the impact of pressure drops in piping systems on energy consumption
  • Explore mathematical modeling techniques for energy consumption analysis
USEFUL FOR

Engineers, energy analysts, and anyone involved in optimizing pump systems and energy efficiency in industrial settings will benefit from this discussion.

mink_man
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Homework Statement



We'll be running a vsd water pump. We'll be seeing the energy savings of using a vsd, instead of using an AC motor on full load and using a tap to reduce water flow. Sorry for the lack of info.



The Attempt at a Solution



I'm sure it will have something to do with mass flow rates or something. But I'm not sure how I'll calculate the energu
 
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I thought some form of bladder tank was used with normal pumps to match the flow rate from the pump to the outlet? eg pump runs until the tank is full then switches off. When you turn on the tap the tank delivers water without running the pump. That continues until the tank is nearly empty then the pump kicks in again. That way the pump is never restricted or loaded up with a partially open tap. I suppose there must be some additional energy consumed inflating the bladder but no idea how to calculate that.
 
Thanks for your reply, but I think you misunderstood.

We're just running a lab experiment to show how a variable speed drive saves money.

We want to run an AC pump at full throttle, then put a restriction in the pipe to reduce mass flow rate. Then we'll run the VSD at a lower speed with no restriction to get the same mass flow rate.
 
In a math model, the energy consumed is the area under the curve of a function, in this case of unit energy per time. For a full throttle motor, the area under the curve is rectangular. For a variable drive, that unit energy per time can vary, resulting in a differing amount of power consumed

Hope this helps
 
I believe the power loss in a restriction/tap is

ΔP * Q

where ΔP is the pressure drop and Q the flow rate. I believe that's the additional power that will need to be provided by the full speed motor (plus losses in the motor).
 

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