How to Calculate force exerted on a falling body?

In summary, the conversation involves an individual seeking to solve the problem of calculating the impact time of a falling object. They consider the force of the object's weight, but after studying various resources and considering the material and structure of the object, they realize they also need to consider the momentum and weight of the object. However, the calculation of impact time is complicated and depends on factors such as the elasticity and shape of the object and the surface it impacts with. The individual seeks to use experimental data and an accelerometer to estimate the impact time and the forces involved in the impact.
  • #1
Chandrasekar
13
1
TL;DR Summary
want to calculate force exerted on a body for that i need to calculate time duration on impact.
I'm curious about impact on falling object, so i have taken initiative to solve this problem.
I considered only force on the falling object would be its weight and taken F=mg. With only limited data m=.25kg and drop height h=1m.
Pondering on this consideration practically, it will have more force than its actual weight.
After Studying on various resources:
1. Link1
2. Link2
3. Link3
4. Link4
5. Link5
6. Link6*
7. Link7*
From this studies i have taken that i need to consider Momentum of the falling body and weight of the body. But in all the solution IMPACT TIME is assumed.
how do i calculate this impact time?
 
Last edited:
Physics news on Phys.org
  • #2
Welcome to PF.

You assume a drop height of 1 metre.
What does it then impact ?
How much time does it take to stop ?
 
  • #3
concrete - rigid base.
How much time does it take to stop ? This is what i want
I can calculate falling time.
i can't calculate the impact time and time taken to stop the object from initial velocity of the impact and 0 final velocity.
 
  • #4
Chandrasekar said:
How much time does it take to stop ?
It depends on what your object is made of and what the floor is made of, and their shapes. This is because the answer depends on how easy it is to deform the object. If you idealise both object and floor as perfectly rigid then the answer is zero time. If, on the other hand, you think of a water droplet then it's just going to splash, and the answer will be on the order of the time it takes the top of the droplet to hit the floor after the bottom touched (over-simplification warning!).

It's a difficult question - there is no single simple formula.
 
  • Like
Likes Lnewqban and Chandrasekar
  • #5
Chandrasekar said:
i can't calculate the impact time and time taken to stop the object from initial velocity of the impact and 0 final velocity.
This is what you need to do: either by your own experiments or researching the topic online. The impact time will also depend on the object. E.g. the force (per unit mass) of impact for a soft object will be less than for a hard object.
 
  • Like
Likes Lnewqban and Chandrasekar
  • #6
i can understand that it depends upon objects elasticity (material property), structure of the body and some energy will loss as heat, then how to calculate it?. what formula do i have to use in order to find it.

The final result, when i drop an object from a height i want to know what will happen to the object, will it break, or damage, solid.

for example when i drop a bottle i want to calculate how much damage it get.

At the beginning it seems very simple problem, as time stretches on study it become complicated to solve :(
 
Last edited:
  • #7
Chandrasekar said:
i can understand that it depends upon objects elasticity (material property) and structure of the body, then how to calculate it?. what formula do i have to use in order to find it.
You need data on the properties of the materials involved.
Chandrasekar said:
The final result, when i drop an object from a height i want to know what will happen to the object, will it break, or damage, solid.
You need experimental data. There isn't just a single formula. Think about the car crash testing that gets done.
 
  • Like
  • Informative
Likes Lnewqban and Chandrasekar
  • #9
Thank you for all who responded to my request, i didn't expected this much response for my query.
but still, even its complicated i want to how to solve it.
 
  • Like
Likes Lnewqban
  • #10
Chandrasekar said:
Thank you for all who responded to my request, i didn't expected this much response for my query.
but still, even its complicated i want to how to solve it.
Using an accelerometer would be the most precise test to perform.

You can at least estimate a reasonable maximum distance the floor and body will deform during impact.

Copied from
https://en.wikipedia.org/wiki/G-force

”After a free fall from a height
h
followed by deceleration over a distance
d
during an impact, the shock on an object is
{\displaystyle (h/d)}
· ɡ0. For example, a stiff and compact object dropped from 1 m that impacts over a distance of 1 mm is subjected to a 1000 ɡ0 deceleration.”
 
  • Informative
Likes Chandrasekar
  • #11
Chandrasekar said:
At the beginning it seems very simple problem, as time stretches on study it become complicated to solve
True statement. Even for people who do this every day.

There is some good discussion of this in this thread: https://www.physicsforums.com/threads/greater-momentum-on-impact-means-greater-force.1049141/. While that thread is about cars smashing into walls, the principles are the same: a rigid impact has higher forces than a soft impact. And it is not always possible to calculate the hardness of the impact, and the resulting forces.
 
  • Like
Likes Lnewqban
  • #12
jrmichler said:
True statement. Even for people who do this every day.

There is some good discussion of this in this thread: https://www.physicsforums.com/threads/greater-momentum-on-impact-means-greater-force.1049141/. While that thread is about cars smashing into walls, the principles are the same: a rigid impact has higher forces than a soft impact. And it is not always possible to calculate the hardness of the impact, and the resulting forces.
i can't find definite answer from this thread. (sorry but on my perspective people are complicating a simple question)
 
  • #13
Chandrasekar said:
i can't find definite answer from this thread.
There wasn't an answer in that thread. There were about 700 different attempts to get the first poster to realise that he had a contradictory mental model of how a crash happened, but no resolution.
Chandrasekar said:
sorry but on my perspective people are complicating a simple question
As they say, "to every question there is an answer that is both simple and wrong". This is one where there is no simple right answer.

This is basically why crash test dummies exist - there isn't a way of working out forces during a car crash except to build a car and slam it into a wall and see what happens. You might be able to build a computer model these days, but I would suspect anything that isn't a cuboid of perfectly elastic material landing flat on one face isn't tractable analytically.
 
  • Like
Likes vanhees71, nasu, PeroK and 1 other person

1. How do I calculate the force exerted on a falling body?

The force exerted on a falling body can be calculated by multiplying the mass of the object by the acceleration due to gravity. This can be represented by the formula F = m x g, where F is the force, m is the mass, and g is the acceleration due to gravity (9.8 m/s^2 on Earth).

2. What is the difference between weight and force in regards to a falling body?

Weight is a measure of the gravitational force acting on an object, while force is a measure of the overall push or pull on an object. In the case of a falling body, weight is the force of gravity pulling the object towards the center of the Earth, while the force exerted on the body is the result of the object's mass and acceleration due to gravity.

3. How does air resistance affect the force exerted on a falling body?

Air resistance, also known as drag, can have a significant impact on the force exerted on a falling body. As an object falls, it encounters air molecules that push against it, creating a force in the opposite direction of its motion. This force increases as the object's speed increases, eventually reaching a point where it is equal to the force of gravity. At this point, the object reaches its terminal velocity, and the force exerted on it remains constant.

4. Can the force exerted on a falling body change during its descent?

Yes, the force exerted on a falling body can change during its descent due to factors such as air resistance, changes in mass, and changes in the acceleration due to gravity. For example, if an object falls from a high altitude where there is less air resistance, it will experience a greater force of gravity compared to the same object falling from a lower altitude.

5. How can I use the force exerted on a falling body to calculate its impact?

The force exerted on a falling body can be used to calculate its impact by multiplying the force by the distance the object falls. This can be represented by the formula W = F x d, where W is the work done, F is the force, and d is the distance. This calculation can help determine the potential damage or force of impact that the falling object may have on its surroundings.

Similar threads

  • Mechanical Engineering
Replies
3
Views
982
  • Introductory Physics Homework Help
Replies
18
Views
2K
Replies
4
Views
768
Replies
1
Views
1K
  • Mechanical Engineering
Replies
26
Views
2K
  • Introductory Physics Homework Help
Replies
7
Views
3K
Replies
11
Views
1K
Replies
26
Views
5K
Back
Top