cashellz77
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Homework Statement
heat Lost Heat Gained
M=.213 kg M=.868
C=2090 J/kg K C=4186 J/kg K
To=0 To=26.5
T=? T=?
Homework Equations
Q=mc(delta T
The discussion focuses on calculating the final temperature in a melting ice scenario involving a 0.213 kg ice cube at 0°C and 0.868 kg of water at 26.5°C. The relevant equations include Q=mcΔT for heat transfer, where Q represents heat, m is mass, C is specific heat capacity, and ΔT is the change in temperature. The heat lost by the water equals the heat gained by the ice, including the heat of fusion required to melt the ice. The final temperature can be determined by equating the heat lost and gained, incorporating the heat of fusion for ice.
PREREQUISITESStudents studying thermodynamics, physics educators, and anyone involved in heat transfer calculations in physical science contexts.
Heat flows from the hotter to the colder until they reach the same temperature. So you know that the temperature of each mass will be the same when equilibrium is reached. You have to determine the final temperature.cashellz77 said:Homework Statement
heat Lost Heat Gained
M=.213 kg M=.868
C=2090 J/kg K C=4186 J/kg K
To=0 To=26.5
T=? T=?
Homework Equations
Q=mc(delta T
The Attempt at a Solution
I can not figure this out , I have tried and tried with no luck.