How to Calculate Heat Loss and Gain in a Melting Ice Scenario?

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SUMMARY

The discussion focuses on calculating the final temperature in a melting ice scenario involving a 0.213 kg ice cube at 0°C and 0.868 kg of water at 26.5°C. The relevant equations include Q=mcΔT for heat transfer, where Q represents heat, m is mass, C is specific heat capacity, and ΔT is the change in temperature. The heat lost by the water equals the heat gained by the ice, including the heat of fusion required to melt the ice. The final temperature can be determined by equating the heat lost and gained, incorporating the heat of fusion for ice.

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Homework Statement



heat Lost Heat Gained
M=.213 kg M=.868
C=2090 J/kg K C=4186 J/kg K
To=0 To=26.5
T=? T=?

Homework Equations



Q=mc(delta T

The Attempt at a Solution

I can not figure this out , I have tried and tried with no luck.
 
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cashellz77 said:

Homework Statement



heat Lost Heat Gained
M=.213 kg M=.868
C=2090 J/kg K C=4186 J/kg K
To=0 To=26.5
T=? T=?

Homework Equations



Q=mc(delta T

The Attempt at a Solution

I can not figure this out , I have tried and tried with no luck.
Heat flows from the hotter to the colder until they reach the same temperature. So you know that the temperature of each mass will be the same when equilibrium is reached. You have to determine the final temperature.
Your equation for the heat flow is correct. So the equations for the change in temperature in terms of initial and final temperature are:

Q_1 = m_1C_1(T_1 - T_f)

Q_2 = m_2C_2(T_f - T_2)

What is the relationship between Q1 and Q2? That will enable you to solve for Tf.

AM
 
Last edited:
Welcome to PF, Cashelz.
I don't think you have typed in the whole question - not exactly sure what the question is!

Generally in these heat questions you write
heat lost by one material = heat gained by the other
mC*ΔT = mC*ΔT

I think your ΔT for the water will be (26.5 - T) where T is the final temperature.
For the other material, looks like ΔT = (T - 0).
Try putting all the info into the equation and see if you can find T.
 
Hello Thankyou! The queastion reads An ice cube with a mass of .213kg and a temp. of0.00c is placed in a Styrofoam cup containing .868 of water at a temp. of 26.5 c . What is the final temp. of the water after the ice cube has melted?
 
Glad you gave us the question! Our previous answers do not apply to this question, which involves the melting of ice. It takes heat to melt ice, called the heat of fusion. So
heat lost by water = heat of fusion of ice + heat gained by ice after melting

You should look up "heat of fusion" in your book and get the formula for it.
 

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