How to Calculate Kinetic Friction: 2 kg Block on Steel Table | Homework Help

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Homework Help Overview

The problem involves a 2 kg steel block at rest on a steel table, with a horizontal string exerting a tension force. The coefficient of kinetic friction is given, and the question seeks to determine the block's speed after moving a specified distance.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the forces acting on the block, including the tension from the string and the frictional force. There are questions about how to calculate the net force and whether the chosen forces will yield the correct acceleration.

Discussion Status

Some participants have provided guidance on identifying the frictional resistance and calculating the net force. There is an acknowledgment of the steps needed to find acceleration and subsequently speed, but no consensus has been reached on the specific approach.

Contextual Notes

Participants are navigating the relationship between tension, friction, and acceleration, with some uncertainty about the correct application of forces in this context.

ceday
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Homework Statement



A 2.00 kg steel block is at rest on a steel table. A horizontal string pulls on the block. The coefficient of kinetic friction of dry steel on steel is μk=.600

If the string tension is 16.0 N, what is the block's speed after moving 1.30 m?


Homework Equations





The Attempt at a Solution




 
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Welcome to PF.

How would you think to solve it?
 
well i know that Fk = μkmg and f=ma

im just not sure what the force should be and if it will give me the right acceleration
 
ceday said:
well i know that Fk = μkmg and f=ma

im just not sure what the force should be and if it will give me the right acceleration

Well what is the frictional resistance?

What force is applied by the string?

What is the net force then?

With the mass you have the acceleration.

And with acceleration you can figure the speed.
 
net force = tension force of the rope - frictional force?
 
got it! thanks for the tips

- chris
 

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