How to Calculate Magnitude and Direction for Orv's Walk?

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SUMMARY

To determine the distance and direction of Orv's second walk, apply the Pythagorean theorem correctly. The first leg of the journey is 312 m due east, and the final position is 220 m northeast of the starting point. The correct approach involves identifying the second leg of the triangle, denoted as 'b', rather than recalculating the hypotenuse. Utilize trigonometric functions (sine, cosine, tangent) to find the angle counterclockwise from the +x-axis.

PREREQUISITES
  • Understanding of the Pythagorean theorem
  • Basic knowledge of trigonometric functions (sine, cosine, tangent)
  • Ability to interpret vector components in two-dimensional space
  • Familiarity with drawing and analyzing right triangles
NEXT STEPS
  • Learn how to apply the Pythagorean theorem in vector problems
  • Study trigonometric identities and their applications in physics
  • Explore vector decomposition techniques for two-dimensional motion
  • Practice solving similar problems involving magnitude and direction
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Students in physics or mathematics, educators teaching vector analysis, and anyone needing to solve problems involving distance and direction in two-dimensional space.

lalahelp
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Homework Statement


Orv walks 312 m due east. He then continues walking along a straight line, but in a different direction, and stops 220 m northeast of his starting point. How far did he walk during the second portion of the trip and in what direction?
What is the magnitude?
What is the direction ___________ ° counterclockwise from the +x-axis



Homework Equations


C=squareroot of 312^2+220^2
What equation to use to find direction??

The Attempt at a Solution


C= Magnitude= 381.76 m why is my magnitude wrong?
 
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A good idea here is to read the problem carefully, and/or make a simple diagram.
You're correct in using the Pythagorean theorem for this problem, but you're using it incorrectly. Remember that the form is a^2 + b^2 = c^2, where c is the hypotenuse.

In the problem statement, you're given a = 312 meters (The distance walked east -- one of the legs of the triangle), and c = 220 meters (The distance in a straight line from the starting point -- the hypotenuse).

This means that what you need to find here is b, not c.
 
As with regards to your direction issues, once you have your three sides figured out, use your trig laws (soh cah toa).

If you've never heard of them, it goes:
"soh" - sin = opposite / hypotenuse
"cah" - cosine = adjacent / hypotenuse
"toa" - tangent = opposite / adjacent

And you should get the right answer.
Cheers

EDIT: or your sin/cosine laws. I didn't work through the problem myself, I just assumed based on the level it was a right angle triangle.
 
Gordanier said:
EDIT: or your sin/cosine laws. I didn't work through the problem myself, I just assumed based on the level it was a right angle triangle.

Same. Now that I look at it (through my sleepy eyes), the 'hypotenuse' is shorter than one of the legs, and by a good bit, too...
 
I can't take the square root of a negative number for the magnitude... Is there another way to solve this...
 
lalahelp said:

Homework Statement


Orv walks 312 m due east. He then continues walking along a straight line, but in a different direction, and stops 220 m northeast of his starting point. How far did he walk during the second portion of the trip and in what direction?
What is the magnitude?
What is the direction ___________ ° counterclockwise from the +x-axis

Did you ever draw it?
 

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@:AC130NAV: The problem states that the final position was 220 m from the starting point in an north easterly direction, so your drawing is not correct.
 
Last edited:

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