How to Calculate Maximum Error in Polar Coordinates

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Homework Help Overview

The discussion revolves around calculating the maximum error in measuring polar coordinates derived from rectangular coordinates, specifically for the point (7.2, 2.5), with a given possible error in each coordinate.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between rectangular and polar coordinates, questioning how to express the errors in terms of polar coordinates. There are attempts to differentiate the polar coordinate equations and relate them back to the Cartesian coordinates.

Discussion Status

Several participants are engaged in clarifying the relationships between the variables and exploring the differentiation process. There is a mix of attempts to derive expressions for the polar coordinates in terms of Cartesian coordinates, with some guidance provided on how to approach the differentiation.

Contextual Notes

Participants are navigating the constraints of expressing polar coordinates solely in terms of the original Cartesian coordinates while considering the potential errors in measurement.

Bryon
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Homework Statement



Rectangular to Polar Coordinates:
I am to find the approximate maximum error in measuring the polar coordinates of the point (7.2, 2.5). There is a possible error of 0.05 in each coordinate.

Homework Equations



dx = deltax
dy = deltay

dz = (partial diff of z with respect to x)dx + (partial diff of z with respect to y)dy

Not sure if I need the following:
x = rcos(theta)
y = rsin(theta)
tan(theta) = y/x


The Attempt at a Solution



I suspect that dx = dy = 0.05

I could set the rectangular coordinates to the polar conversions but I am not sure how that helps:

7.2 = rcos(theta)
2.5 = rsin(theta)

This is where I am held up at and not sure how to go about solving this one.
 
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What are dr and d\theta in terms of dx and dy?
 
Would I be differentiating r = y/sin(theta) theta = arcin(y/r) and r = x/cos(theta) theta = arccos(x/r)?
 
Bryon said:
Would I be differentiating r = y/sin(theta) theta = arcin(y/r) and r = x/cos(theta) theta = arccos(x/r)?

Close, but get the r's out of your \theta formulas and the \theta's out of your r formulas.
 
Ah, all I have to do is substitute r for r = y/sin(theta) in theta = arcsin(y/r) which would be
theta = arcsin(y/ysin(theta)) and so on! Thanks!
 
No, you need the r's and \theta's entirely in terms of the original Cartesian coordinates.
 
I figured it out! Thank you very much!
 

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