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How to calculate mutual inductance of a rectangular loop

  1. May 12, 2015 #1
    I am planning to build a rogowski coil but not the conventional one, which is a circular loop.
    Below is the example of a rogowski coil so you have the big picture of my question.

    CurrentSensor-Rogowski_ill.jpg

    In the picture, the current conducting wire (with current Ip) is encircled by a big circular loop rogowski coil. The cross sectional area of the winding itself can be a circle, rectangle, or oval.
    For this variations of cross sectional area, I know how to calculate the mutual inductance.

    However, what if the shape of the big loop is rectangular? How to calculate the mutual inductance?

    I hope you all can help me figure this out.
     
  2. jcsd
  3. May 12, 2015 #2

    Hesch

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    Think of Amperes law, which in this case could be formulated:

    circulation H⋅ds = Ip

    ( B = μ0*H )

    What happens if you choose a rectangle as integration path instead of a circle?
     
  4. May 13, 2015 #3
    Let's see. Suppose I is 1kA.
    So:

    circulation B⋅ds = Ip0

    circulation B⋅ds = 1000 A * 4π*10-7 Vs/Am = 4π*10-4

    So then, how is the B ?
     
    Last edited: May 13, 2015
  5. May 13, 2015 #4

    Hesch

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    Forget B for a moment. Let's look at H when Ip = 1000A and radius for the "big loop" = R, according to your drawing in #1:

    circulation H⋅ds = 1000A

    Now you choose a circulation path through the "small loops", giving:

    H = 1000A / (2πR). Here 2πR is the length of the rogowski coil = L ⇒ H = 1000A / L.

    Now you bend the the coil into a rectangle, and you choose a circulation path following this rectangular shape. The length of the rogowski coil is still the same = L, you have just bended it. So now Hmean = 1000A / L. This means that

    Hmean = H ⇒
    Bmean = B ⇒
    Vicircle = dψv/dt = Virect. ( Ψv = flux * turns )

    According to the definition: Vi = -M × dIp/dt ⇒
    Mrect = Mcircle
     
    Last edited: May 13, 2015
  6. May 18, 2015 #5
    Okay, let's say Mrect = Mcircle

    And suppose the small loop is rectangular as well.


    img.png

    To calculate M:

    c1.png

    So:
    c2.png

    The integration is easy since the distance x from the current wire to the coil is all the same because of circular symmetry of the big loop. However, if the big loop is rectangular, the distance x will be different for each small loop. Also, it will make a and b change all the time as well. So, how to calculate this?
     
    Last edited: May 18, 2015
  7. May 18, 2015 #6

    Hesch

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    You may calculate it using Biot-Savart law, but that is comprehensive.

    I think that the idea is to look at: circulation H⋅ds = 1000A. This equation is valid no matter what circulation path you choose. Now say that the distance between two windings in the rogowski coil is very small ( ds ), and the length of the big loop is constant, then the mean value of H will be the same as for rectangular/circular shape of the big loop.

    Hmean = constant → Bmean = constant → Ψv = constant → Vi = constant → M = constant. ( Ψv = flux * ( number of windings ) ).

    So the idea is to regard the rectangular big loop as a circular loop as you will get the same result in calculations under the conditions:

    Same length of the big loop, same number of turns in the rogowski coil, same cross section area of the rogowski coil, the rogowski coil is completely surrounding the conductor (closed loop).
     
    Last edited: May 18, 2015
  8. May 18, 2015 #7
    Okay then. I will try to make both coils and compare the result. Thanks a lot.
     
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