How to calculate the density of an iron nucleus

[matt_crouch]

Homework Statement

An iron nucleus has a radius of 5.4x10^-15 and a mass of 9.3x10^-26 what is its mass per unit volume in kg/m^3

Homework Equations

Area of a sphere = 4/3(pi)r^3
Density= M/V

The Attempt at a Solution

i basically plugged everything into the equations so calculated the volume and put it into the density equation but my answer is far to high i think

im getting 1.4x10^17 kgm^-3

just need some clarification on how to complete it or if I am right or not

 

[willem2]

your calculation is Ok.
the size of an iron atom is 1.4*10^-10 m. This means that the radius of the core is about 26000 times smaller, and the volume is 26000^3 smaller, so about 1.7*10^13 times smaller.
If you compress iron until all the empty space between the cores is filled in it will become 1.7*10^13 times more dense.

 

[matt_crouch]

ok thanks just wanted to check =]