How to Calculate the Magnetic Field in a Toroid?

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SUMMARY

The discussion focuses on calculating the magnetic field in a toroid with specific parameters: a current (I) of 7.10 Amperes, 820 turns (N), and inner and outer radii of 23.0 cm and 27.6 cm, respectively. The correct formula for the magnetic field (B) in a toroid is B = (μ₀ * I * N) / (2 * π * r), where r is the radius at which the magnetic field is being calculated. Participants clarified that the initial formula presented by the user was incorrect and sought to confirm the proper variables and constants involved in the calculation.

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  • Understanding of Ampere's Law
  • Familiarity with magnetic field calculations
  • Knowledge of toroidal geometry
  • Basic physics concepts related to electromagnetism
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  • Study the derivation of Ampere's Law in the context of toroids
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dangish
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The toroid shown in the figure has a wire carrying a current I= 7.10 Amperes wrapped around it N= 820 times. The inner radius is R1 23.0 cm and outer radius R2 27.6cm.

Figure:
http://capaserv.physics.mun.ca/msuph...ob01_torus.gif


What is the magnitude of the magnetic field along a circle that is halfway between the inner and outer edges of the toroid?

Here is what I tried,

B = u0*I*r*N / (2Pi*R^2)

maybe I have to divide N by the current and replace the N in my equation above by N/I??

Please help
 
Last edited by a moderator:
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dangish said:
Here is what I tried,

B = u0*I*r*N / (2Pi*R^2)

maybe I have to divide N by the current and replace the N in my equation above by N/I??

Please help
That formula doesn't look right. Where did you get it from, and what are r and R?
 

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