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How to calculate the ratio of weight?

  1. Feb 6, 2012 #1
    1. The problem statement, all variables and given/known data
    Two body move apart by force. Frictional forces are considering. How to calculate the ratio of weight?
    m1<m2
    Ft1=k*g*m1
    Ft2=k*g*m2

    2. Relevant equations
    v1(t1)=[itex]\frac{F_{t1}-F}{m_{1}}[/itex]*t[itex]_{1}[/itex]
    x1(t1)=[itex]\frac{F_{t1}-F}{m_{1}}[/itex]*[itex]\frac{t^{2}_{1}}{2}[/itex]

    v2(t1)=[itex]\frac{F-F_{t2}}{m_{2}}[/itex]*t[itex]_{1}[/itex]
    x2(t1)=[itex]\frac{F-F_{t2}}{m_{2}}[/itex]*[itex]\frac{t^{2}_{1}}{2}[/itex]

    What is the procedure of calculation.
    Thank you for your help.
     

    Attached Files:

  2. jcsd
  3. Feb 6, 2012 #2

    tiny-tim

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    welcome to pf!

    hi asteorit! welcome to pf! :smile:

    sorry, but i don't understand the set-up :redface:

    what is the connection between these two bodies?
     
  4. Feb 7, 2012 #3
    Re: welcome to pf!

    Hi tiny-tim,

    These two bodies are connected by linear actuators. Force F of the linear actuator, will act on both the bodies. We know that the bodies should move along the path L, L=x1(t1)+x2(t1). We know that m1<m2.
    If I assume correctly, and the trajectory of bodies depends on the mass ratio. Or is also dependent on the time t1?
    What is the ratio of the mass of bodies[itex]\frac{m_{2}}{m_{1}}[/itex]=?, if the sum of their orbits must be equal to L?
     
  5. Feb 7, 2012 #4

    tiny-tim

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    hi asteorit! :wink:

    i see … so it's equal-and-opposite-reaction-forces, but without contact

    ok, then start by writing out Ftotal = ma for each body …

    what do you get? :smile:
     
  6. Feb 7, 2012 #5
    I do not understand it, to me you ask? Some will not understand it?
    Because I need to know what is the ratio of the masses.
     
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