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How to calculate the wetted perimeter

  1. Mar 17, 2014 #1
    1. The problem statement, all variables and given/known data
    So I have been taught that the wetted perimeter is the perimeter in which the surface is wet. So in the case for internal forced convection of a thick wall pipe I would have thought the perimeter would be 2*pi*r where r is the inner radius of the pipe. However, doing a bit of googling, this answer is clearly wrong as shown in the image below:
    zyObkrl.png

    Does anyone know why?
     
  2. jcsd
  3. Mar 17, 2014 #2
    Yes. This is not a thick walled pipe calculation. It is a calculation of axial flow along an annular channel (between two concentric cylinders).

    Chet
     
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