How to calculate this integral for harmonic function?

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kakarotyjn
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I was asked to seek for a harmonic function u(x,y) in the 2-dimension disk whoes boundary condition is [tex]u\mid_C=A\cos(\phi)[/tex],the I need to calculate the integral [tex]u(\rho_0,\theta_0)=\frac{1}{2\pi}\int_0^{2\pi}\frac{(R^2-\rho_0^2)A\cos(\theta)}{R^2-2R\rho_0\cos{(\theta-\theta_0)}+\rho^2}d\theta[/tex],but I don't know how to calculate.

Thank for any ideas:smile:
 
With appropriate changes in coefficients, it is possible to transform the integral to the next know integral :
 
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  • Definite integral from 0 to 2π of c cos(x) divided by 1 + a cos(x) + b sin(x) dx, equal to 2πac/(a²+b²) times (1 − 1/√(1 − a² − b²)), with the condition a² + b² < 1.
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