How to calculate this integral for harmonic function?

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SUMMARY

The discussion focuses on calculating the integral for a harmonic function u(x,y) defined in a 2-dimensional disk with boundary condition u|_C = A cos(φ). The integral to be evaluated is u(ρ₀, θ₀) = (1/2π) ∫₀²π ((R² - ρ₀²)A cos(θ)) / (R² - 2Rρ₀ cos(θ - θ₀) + ρ²) dθ. Participants suggest that with appropriate changes in coefficients, this integral can be transformed into a known integral, facilitating its evaluation.

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I was asked to seek for a harmonic function u(x,y) in the 2-dimension disk whoes boundary condition is [tex]u\mid_C=A\cos(\phi)[/tex],the I need to calculate the integral [tex]u(\rho_0,\theta_0)=\frac{1}{2\pi}\int_0^{2\pi}\frac{(R^2-\rho_0^2)A\cos(\theta)}{R^2-2R\rho_0\cos{(\theta-\theta_0)}+\rho^2}d\theta[/tex],but I don't know how to calculate.

Thank for any ideas:smile:
 
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With appropriate changes in coefficients, it is possible to transform the integral to the next know integral :
 

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