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- Thread starter ferret_guy
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I have used numerical integration with this __energy__ loss rate (see http://en.wikipedia.org/wiki/Drag_(physics [Broken]))

[tex] \frac{dE}{dt}=\frac{1}{2}\rho \cdot C_{drag} \cdot A \cdot v^{3} \text { Newton meters per second} [/tex]

The force is [tex] F=\frac{1}{2}\rho \cdot C_{drag} \cdot A \cdot v^{2} \text { Newtons} [/tex]

[tex] \frac{dE}{dt}=\frac{1}{2}\rho \cdot C_{drag} \cdot A \cdot v^{3} \text { Newton meters per second} [/tex]

The force is [tex] F=\frac{1}{2}\rho \cdot C_{drag} \cdot A \cdot v^{2} \text { Newtons} [/tex]

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The reason Bob S used numerical integration is because that is pretty much the only choice. There is no closed form solution in the elementary functions. There was a buzz a month ago or so about some kid in Germany who claimed to have found such a closed form solution. He didn't. He found a slowly converging series solution (that's not "closed form"), and what he found is well known and is also well known as pretty much useless. There is no simple closed form solution to this problem.I have used numerical integration

As a historical note, the problem of a ballistic object with drag was one of the driving forces (if not

ferret_guy: Note that this is the magnitude of the drag force. The direction is always against the velocity vector.The force is [tex] F=\frac{1}{2}\rho \cdot C_{drag} \cdot A \cdot v^{2} \text { Newtons} [/tex]

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I usually do it once per millisecond until the object lands.

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