How to change ∅ in term of x? (integration by trigonometry substitution)

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SUMMARY

The integral ∫dx/(x²√(x²-1)) can be solved using trigonometric substitution by letting x = a sec ∅. This substitution transforms the integral into ∫cos ∅ d∅, which evaluates to sin ∅ + C. To express sin ∅ in terms of x, one must visualize a right triangle where the hypotenuse is x and the adjacent side is a, leading to the opposite side being √(x² - a²). This geometric interpretation allows for the conversion of sin ∅ back into a function of x.

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clifftan
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the question is ∫dx/ x^2*√(x^2-1)

I use x=a sec ∅ x^2*√(x^2-1)= sec^2∅tan∅ x=sec ∅
dx= sec∅tan∅d∅

so it will become something like this ∫sec∅tan∅d∅/sec^2∅tan∅= ∫1/sec∅d∅=∫cos∅d∅
=sin∅+c
But how can i change this sin in term of x?
 
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You said [itex]x = a \sec \theta[/itex].

Can you draw a right triangle for which this is true and solve for the lengths of each of the sides?
 

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