How to Compute F on a Given Surface with Downward Pointing Normal?

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lembeh
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Homework Statement



Let S be the surface given by the graph z = 4 - x2 - y2 above the xy-plane (that it is, where z [tex]\geq[/tex] 0) with downward pointing normal, and let

F (x,y,z) = xcosz i - ycosz j + (x2 + y2 ) k

Compute [tex]\oint\oints[/tex][tex]\oint[/tex]s F dS. (F has a downward pointing normal)

(Hint: Its easy to see that div F = 0 on all R3. This implies that there exists a vector field G such that F = Curl G, although it doesn't tell you what G is)



Homework Equations



z = 4 - x2 - y2 above the xy-plane (that it is, where z [tex]\geq[/tex] 0) with downward pointing normal

F (x,y,z) = xcosz i - ycosz j + (x2 + y2 ) k

Compute [tex]\oint\oints[/tex][tex]\oint[/tex]s F dS. (F has a downward pointing normal)

The Attempt at a Solution



Im getting throw off a bit by the hint. I know its something to do with the surface not being defined around the origin but that's about it.

Homework Statement



See above

Homework Equations



How do I solve this?!
 
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Right, but how do I compute this? My daughter hasnt gone past Green's theorem yet in class...I saw this problem on her homework but she couldn't solve it. I can help her and know some Multivariable calculus (but not vector calculus). I want to help her get through this. I would really appreciate it if someone spelt out the solution for me. So I could learn this and help her out with this. I hope that's not an unreasonable request :)