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## Homework Statement

r(t) = <cos(t), 2t, sin(t)> from 0 to 2pi (included).

Compute the integral from 0 to 2pi of r(t).

## Homework Equations

## The Attempt at a Solution

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We haven't learned this in class yet, so I am getting a head. My idea is to simply put r(t) in and integrate term by term so that the final answer is

sin(t), t^2, -cos(t) and evaluate it from 0 to 2pi which gets

<0, 4pi^2, -1> - < 0, 0, -1>

which results in

<0, 4pi^2, 0>

And then I take the magnitude? Eh, answer should not be a vector I assume since this is the area of the space.

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