- #1
clifftan
- 3
- 0
the question is ∫ √(y^2-25)/y^3 dy..
I did found the answer which is 1/5 sec^-1(y/5)-sin2∅/20-∅/10
But mine tutorial answer is 1/5 sec^-1(y/5)- √(y^2-25)/2y^2+c
i don't know how to convert the behind part sin2∅/20-∅/10 into √(y^2-25)/2y^2
I did found the answer which is 1/5 sec^-1(y/5)-sin2∅/20-∅/10
But mine tutorial answer is 1/5 sec^-1(y/5)- √(y^2-25)/2y^2+c
i don't know how to convert the behind part sin2∅/20-∅/10 into √(y^2-25)/2y^2