How to Convert Sine and Cosine to Secant for Integration?

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techniques of inegration, please help

in the attachment there is a problem related to techniques of integration, i fully understand everything until near the end of the problem they answer says

(1/6)o - (1/12)sin2o + C = (1/6)o - (1/6)sino coso + C

and then they convert the sinocoso to sec-1

this part is really confusing...can you help me please...

thank you
 
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abot said:
In the attachment there is a problem related to techniques of integration, i fully understand everything until near the end of the problem they answer says
(1/6)o - (1/12)sin2o + C = (1/6)o - (1/6)sino coso + C
?
But... there's no attachment? :confused:
 
Do you know the "double angle formula":
[tex]sin(2\theta)= 2sin(\theta)cos(\theta)[/tex]

That was what was used.

I'm not clear what you mean by "convert the sin([itex]\theta[/itex])cos([itex]\theta[/itex]) to sec-1"
Of course, sec([itex]\theta[/itex]) is defined as [itex]\frac{1}{cos(\theta)}[/itex] so if that "-1" is meant as reciprocal rather than "inverse function", it is true that
[tex]sin(\theta)cos(\theta)= \frac{sin(\theta)}{sec(\theta)}[/tex]