How to correctly convolve two delta functions?

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SUMMARY

The convolution of two delta functions, represented as ##\delta(\omega) \otimes \delta(\omega)##, is computed using the integral $$\int_{-\infty}^\infty \delta(\omega-\Omega)\delta(\Omega) d\Omega$$. This integral evaluates to ##\delta(\omega)## when both conditions ##\omega - \Omega = 0## and ##\omega = 0## are satisfied. The initial assumption that the result is ##2\delta(\omega)## is incorrect; the correct treatment confirms that the convolution yields only ##\delta(\omega)##.

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badkitty
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How do I correctly compute the convolution of two delta functions? For example, if I want to compute ##\delta(\omega)\otimes\delta(\omega)##, I should integrate $$\int_{-\infty}^\infty \delta(\omega-\Omega)\delta(\Omega) d\Omega$$
This integrand "fires" at two places: ##\Omega = 0## and ##\Omega = \omega##, and evaluates to ##\delta(\omega)## in either case. That leads me to say that ##\delta(\omega)\otimes\delta(\omega) = 2\delta(\omega)##, which somehow feels wrong... I want it to be just ##\delta(\omega)##.

Anyone know the correct treatment here?
 
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In your example, ##\int_{-\infty}^\infty \delta(\omega-\Omega) \delta(\Omega) \, d\Omega## is only non-zero if both ## \omega - \Omega = 0 ## and ## \omega = 0 ##.
So for this, you end up with ##\delta(\omega)##.
 

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