I How to correctly mark event B on the picture?

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The discussion centers on identifying the location of event B in a photon clock scenario, where the clock's movement is analyzed from two different frames of reference. In the first frame, the clock moves to the right, while in the second frame, it is at rest. Participants clarify that event A is directly above event B in both frames, and the equations provided illustrate the relationship between the two scenarios. The Principle of Relativity is emphasized, indicating that both frames are reversible. Clear descriptions of events A and B are suggested to resolve any confusion regarding their positions.
Mike_bb
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Hello!

I have photon clock that moves to right side with velocity V.
In the first case events A and B are depicted on the picture on the top side:

1.jpg


In accordance with the Principle of Relativity I obtained second case.
But I can't mark event B in the second case on the bottom side. Where is event B located in this case?

Thanks!
 
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I guess you describe the same events A and B from the viewpoint of two different frames: In the first frame (upper image), the light clock moves to the right, in the second frame (lower image) it moves to the left. If that's the case, then event B on the lower image is located in the middle of the left-bottom mirror where it meets the arrow.
 
It's difficult to know because you haven't described the experiment clearly. @Histspec's guess is reasonable and may be correct, but it's a guess.

You say the clock is moving to the right. Presumably that's in the top picture. Is it supposed to be moving to the left in the lower picture? That's what I would guess, but that's an unusual thing to do with a light clock since it doesn't really gain you anything. What's the extra quantity ##t_0## in the srcond diagram? How does it relate to anything else? Is the shading of the mirrors meant to be indicative of something? And what are events A and B supposed to be?

In particular, if you write down a description of A and B I suspect you will answer your own question.
 
Ibix said:
It's difficult to know because you haven't described the experiment clearly. @Histspec's guess is reasonable and may be correct, but it's a guess.

You say the clock is moving to the right. Presumably that's in the top picture. Is it supposed to be moving to the left in the lower picture? That's what I would guess, but that's an unusual thing to do with a light clock since it doesn't really gain you anything. What's the extra quantity ##t_0## in the srcond diagram? How does it relate to anything else? Is the shading of the mirrors meant to be indicative of something? And what are events A and B supposed to be?

In particular, if you write down a description of A and B I suspect you will answer your own question.
In the top picture clock is moving to right. But in the lower picture clock is rest. (In accordance with Principle of Relativity)

$$c^2\Delta t^2-\Delta x^2 = c^2\Delta t_0^2-\Delta x'^2$$
 
Mike_bb said:
In the top picture clock is moving to right. But in the lower picture clock is rest.
Then, in the second picture there is no velocity ##v## and no moving clock. Event A occurs directly above event B.
 
PeroK said:
Then, in the second picture there is no velocity ##v## and no moving clock. Event A occurs directly above event B.
These equality for first and second picture:

$$c^2\Delta t^2-\Delta x^2 = c^2\Delta t_0^2-\Delta x'^2$$
$$c^2\Delta t_0^2-\Delta x'^2 = c^2\Delta t^2-\Delta x^2$$

In accordance with Principle of Relativity we have that first frame and second frame are reversable. It's shown on the first and second picture.
 
PeroK said:
Event A occurs directly above event B.
Thanks. It's right!