How to Create an Average Velocity vs. Time Graph from Collected Data Points

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To create an average velocity vs. time graph from the provided data points, average velocity must be calculated for each segment between points using the formula Avg. Velocity = (x-x0)/(t-t0). The time component for plotting these average velocities is determined by the time intervals between the data points, specifically from the start to the end of each interval. It is suggested to use the midpoint of each time interval for more accurate representation. Clarification is needed on whether to graph the calculated average velocities directly or to apply a least squares regression method.
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Homework Statement



Make a graph of the average velocity vs. time using data points collected.

Data points:
(0.8023 s, 0.606 m)
(0.9027 s, 0.710 m)
(1.0031 s, 0.816 m)
(1.1035 s, 0.912 m)
(1.2039 s, 1.023 m)
*s = seconds
*m = meters

Homework Equations



Avg. Velocity = (x-x0)/(t-t0)

The Attempt at a Solution



I calculated the average velocity for each segment (ie. from point 1 to point 2 and so on), but I'm not sure how to come up with the time component of the ordered pair of the average velocity points.

 
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You'd plot the average velocity over the time you calculated for... for example the average velocity you got using (0.8023 s, 0.606 m) and (0.9027 s, 0.710 m)... you plot that average velocity number over the times 0.8023s to 0.9027s...

So you'll have a bunch of horizontal straight line segments...
 
So I presume you started with

\frac{x_1 - x_0}{t_1 - t_0} = v_1 = .606/.802

This gives the average velocity of the time interval [0, .802]. So whatever the average velocity is you should have that value go from 0 to .802. Does this help? I'm not really sure what you mean.
 
Rather calculate the average velocity with

v_{avg} = \frac{x_{n+1} - x_n }{t_{n+1} - t_n}

It is not clear from your data what is given, the change in distance and time, or just the distance and time. My guess is that it is the second case.

Take the time for the average speed in the middle of each time interval, that is the time from the beginning up to the middle of the interval where the average speed was calculated.
 
The data is just the distance that a cart traveled along a track at different times.
And thanks for the help everyone, I hope I can figure out with your advice. :)
 
I don't really get it... ARe you supposed to graph the points and find a least squares regression, are are you actually calculating the average velocity? If you're calculating the average velocity you need to give a time interval...
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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