# How to find maximum force on a velocity vs time graph

• AnonymousAnonymous
In summary, to find the maximum force on a velocity vs time graph, one would need to find the point of inflection where the concavity of the function shifts from concave down to concave up. This indicates a local maximum, which corresponds to the maximum acceleration and therefore the maximum force. This point can be estimated by finding the slope of the curve at that point, which can be easily done using the graph provided.
AnonymousAnonymous
Homework type question moved from technical forum, hence template not shown.
The velocity versus time graph is the following:

http://imgur.com/kyebx8H

As the title asks, how would you find the maximum force on a velocity vs time graph given nothing but the graph and the mass of the object in question. My reasoning was that since f = ma and m is never changing, that the time at which the maximum force would be applied when dv/dt is greatest. However, since a function is not provided, one would find this point (in this case, the point of inflection) by finding where the concavity of the function shifts from concave down to concave up, indicating a local maximum (maximum acceleration and therefore maximum force) which is at t=0.35s. I'm stuck on how you would find the maximum force from this and would appreciate any help.

AnonymousAnonymous said:
... f = ma ...dv/dt...I'm stuck on how you would find the maximum force from this ...
You have all you need in your post.

AnonymousAnonymous said:
The velocity versus time graph is the following:

http://imgur.com/kyebx8H

As the title asks, how would you find the maximum force on a velocity vs time graph given nothing but the graph and the mass of the object in question. My reasoning was that since f = ma and m is never changing, that the time at which the maximum force would be applied when dv/dt is greatest. However, since a function is not provided, one would find this point (in this case, the point of inflection) by finding where the concavity of the function shifts from concave down to concave up, indicating a local maximum (maximum acceleration and therefore maximum force) which is at t=0.35s. I'm stuck on how you would find the maximum force from this and would appreciate any help.

You should be able to estimate the slope at that point from the graph. It even looks like the curve between v= +0.1 to -0.1 m/s is almost a straight line. So you can easily find the slope.

Zz.

## 1. What is the meaning of maximum force on a velocity vs time graph?

The maximum force on a velocity vs time graph is the highest value of force that is reached during the motion of an object. It represents the maximum amount of force that is exerted on the object at any given point in time.

## 2. How is the maximum force determined on a velocity vs time graph?

The maximum force can be determined by finding the steepest slope on the graph. This corresponds to the point where the velocity is changing the fastest, and therefore, the force is at its peak.

## 3. Can the maximum force be negative on a velocity vs time graph?

Yes, the maximum force can be negative on a velocity vs time graph. This would occur when the velocity is decreasing over time, resulting in a negative slope and a negative force value.

## 4. How is the maximum force related to the acceleration of the object?

The maximum force is directly related to the acceleration of the object. This is because acceleration is defined as the rate of change of velocity, and force is responsible for causing changes in an object's velocity. Therefore, the higher the maximum force, the greater the acceleration of the object.

## 5. What factors can affect the maximum force on a velocity vs time graph?

The maximum force on a velocity vs time graph can be affected by several factors, such as the mass of the object, the force applied to the object, and any external forces acting on the object. Additionally, the shape of the graph can also impact the maximum force, as a steeper slope indicates a higher force value.

Replies
6
Views
1K
Replies
9
Views
457
Replies
11
Views
1K
Replies
1
Views
3K
Replies
5
Views
2K
Replies
23
Views
2K
Replies
1
Views
1K
Replies
2
Views
2K
Replies
1
Views
5K
Replies
6
Views
2K