Undergrad How to derive Non-normalized quaternion with respect to time?

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SUMMARY

The derivative of a non-normalized quaternion, denoted as q, can be expressed using the formula $$\dot{q}=\left|q\right|\dot{\hat{q}}+\hat{q}\frac{d\left|q\right|}{dt}$$. This approach incorporates the time-dependent magnitude of the quaternion, |q|, and the normalized quaternion $$\hat{q}$$. The discussion highlights the complexity of deriving this expression, emphasizing that without additional constraints, the resulting expression remains general and arbitrary.

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  • Knowledge of calculus, specifically the chain rule
  • Basic concepts of time-dependent functions
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Roni BM
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I know that for normalized quaternion, $$\hat{q}$$, the derivative is given by $$\frac{d\hat{q}}{dt}=\frac{1}{2}\hat{q}\cdot \omega$$ where $$\cdot$$ denotes the quaternion multiplication.

I want to calculate the time derivative of a non-normalized quaternion q.

I tried to calculate the derivative by using the chain rule, $$\dot{q}=\left|q\right|\dot{\hat{q}}+\hat{q}\frac{d\left|q\right|}{dt}$$ and I got a very complicated term. I wonder if I am having a wrong approach and if there is a known formula?
 
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I assume you have a time dependent radius ##|q|##, which means you have an arbitrary path in a four dimensional real space. So without any further information, the expression is necessarily general and arbitrary.
 
Relativistic Momentum, Mass, and Energy Momentum and mass (...), the classic equations for conserving momentum and energy are not adequate for the analysis of high-speed collisions. (...) The momentum of a particle moving with velocity ##v## is given by $$p=\cfrac{mv}{\sqrt{1-(v^2/c^2)}}\qquad{R-10}$$ ENERGY In relativistic mechanics, as in classic mechanics, the net force on a particle is equal to the time rate of change of the momentum of the particle. Considering one-dimensional...

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