How to derive the branch cuts for complex arcsin(z)

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
1 reply · 3K views
monmon_4
Messages
15
Reaction score
0
I notice that the branch cuts for arcsin(z) are from -infinity to -1 and 1 to infinity. How do these choices for the branch cuts make the function single-valued? I am having trouble understanding the reasoning here even though these choices for the cuts are widely used/accepted.
 
Physics news on Phys.org
I believe that any two paths from -1 and 1 to infinity that don't intersect themselves or each other (i.e. leaves the complex plane connected) will work. The standard ones seem like a good choice. They are simple and symmetric wrt the real axis.