How to describe characteristics a parabola?

  • Context: High School 
  • Thread starter Thread starter decadyne
  • Start date Start date
  • Tags Tags
    Parabola
Click For Summary
SUMMARY

This discussion focuses on the characteristics of a parabola as it relates to the trajectory of a mass in uniform gravity. The key points include the understanding that the vertical-axis velocity of the parabola is zero at its apex, confirming the object's upward and downward velocities. The trajectory can be predicted using the principles of force and momentum, specifically through the equation v = v0 - 9.8t, where v0 is the initial upward velocity and g is the gravitational constant (-9.8 m/s²). The discussion emphasizes the importance of differentiating between the object's velocity and the parabola's derivative.

PREREQUISITES
  • Understanding of basic physics concepts, particularly force and motion.
  • Familiarity with calculus, specifically integration and derivatives.
  • Knowledge of gravitational force and its effects on motion.
  • Ability to interpret mathematical equations related to motion.
NEXT STEPS
  • Study the principles of projectile motion in physics.
  • Learn about the mathematical derivation of parabolic trajectories.
  • Explore the applications of calculus in physics, particularly in motion analysis.
  • Investigate the effects of friction on parabolic trajectories in real-world scenarios.
USEFUL FOR

Students of physics, educators teaching kinematics, and anyone interested in understanding the mathematical modeling of motion under gravitational forces.

decadyne
Messages
1
Reaction score
0
Help me understand the components of a parabola as created by a physical object in normal gravity.

The object has some forward velocity, some upward velocity, and at some point some downward velocity. Is this correct?

Is it safe to say, therefore, that at some point the parabola's vertical-axis velocity is zero? This is at the apex, correct?

Please tell me more about how to describe it, and if my assumptions are correct. Are there any other places where its characteristics can be predicted?
 
Physics news on Phys.org
The parabola you seem to be discussing is the trajectory of a mass with some initial velocity in an environment with uniform gravity and no friction. The properties you have listed are correct. But when you say "the parabola's velocity", what you mean to say is either "the object's velocity" or "the parabola's derivative". A derivative is the mathematical property of a geometric shape that corresponds to the concept of velocity of the object in this case.

All of the characteristics of the parabolic trajectory can be predicted. Are there any in particular that you are curious about? In this case, the forward velocity is always the same (since there is no friction, and since gravity has no component in that direction and therefore no effect in that direction). The vertical velocity at every point in time can be computed using the definitions of force (F=dp/dt) and momentum (p=mv) and a little simple calculus, bearing in mind that "uniform gravity" means the gravitational force is always downward and always the same number. Specifically,

F = dp/dt = d(mv)/dt = m dv/dt.

Then, integrating both sides,

t F = m (v + v0).

So,

v = v0 + (t F / m),

where v is the upward velocity at time t, v0 is the upward velocity at time t=0, F is the force of gravity (which should be a negative number because it is downward), and m is the mass of the object. Since the force due to gravity on Earth is g m, where g=-9.8 m/s/s, we can be even more specific:

v = v0 + (t g m / m) = v0 + t g = v0 - 9.8 t,

Where v and v0 are in m/s and t is in seconds.

Does that about clear it up?
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 169 ·
6
Replies
169
Views
15K
  • · Replies 7 ·
Replies
7
Views
847
  • · Replies 15 ·
Replies
15
Views
1K
  • · Replies 10 ·
Replies
10
Views
778
  • · Replies 31 ·
2
Replies
31
Views
6K
  • · Replies 60 ·
3
Replies
60
Views
6K
  • · Replies 25 ·
Replies
25
Views
4K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 49 ·
2
Replies
49
Views
4K