How to Determine and Visualize Integration Limits in 3D Surfaces?

Click For Summary

Homework Help Overview

The problem involves determining the volume between two surfaces defined by the equations z = 3 - 2y and z = x^2 + y^2. The focus is on finding the limits of integration for this three-dimensional scenario.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss setting the equations equal to find intersections and suggest plotting in the xy plane to establish limits. Questions arise about visualizing the surfaces and confirming which surface is above the other without explicit information.

Discussion Status

The discussion is ongoing, with participants exploring different methods to visualize the surfaces and clarify their relationship. Some guidance on visual representation has been provided, but multiple interpretations and uncertainties remain regarding the setup.

Contextual Notes

Participants express concern about the implications of not having explicit information regarding the relative positions of the surfaces, which adds complexity to the problem. The challenge of visualizing the three-dimensional context is noted.

BrownianMan
Messages
133
Reaction score
0
Find the volume lying below z = 3 - 2y and above z = x^2 + y^2.

How would I go about finding the limits of integration for this problem?
 
Physics news on Phys.org
Set the z's equal and plot the resulting xy equation in the xy plane to figure out the limits.
 
Thanks.

What if the question did not specify that z = 3 - 2y was above z = x^2 + y^2? How would I determine that it was in fact above it? I'm having some trouble visualizing all of this in 3 dimensions.
 
BrownianMan said:
Thanks.

What if the question did not specify that z = 3 - 2y was above z = x^2 + y^2? How would I determine that it was in fact above it? I'm having some trouble visualizing all of this in 3 dimensions.

The usual way to help visualize things like this is to draw a picture of the surface. You should be able to recognize one as a paraboloid and the other a plane.
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
6
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K