- #1

Dragonfall

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[tex]aR'b \Leftrightarrow ((\forall x \in a_M\exists y\in b_M xRy) \wedge (\forall x \in b_M\exists y\in a_M xRy))[/tex]

where [tex]a_M[/tex] is the set of children of a in M.

So let ~ be the relation on the class of all sets V such that a~b iff there exists an accessible pointed graph that is the picture of both a and b.

An accessible pointed graph is a directed graph with a distinguished node from where every other node is connected by a path.

Show that ~ is a bisimulation.

I'm not sure what bisimulation says. Can someone explain it in more familiar terms?