How to determine numerically the diode current

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SUMMARY

This discussion focuses on determining the diode current I(D) for both t<0 and t>0 using numerical and graphical methods. The circuit parameters provided include resistances R1, R2, and R3, each at 100Ω, and a current I0 of 24 mA. The open circuit current (I_oc) is 0 mA at a Thevenin voltage (V_Th) of 1.2 V, while the short circuit current (I_sc) is calculated to be 8.0 mA. The working point for the diode is established graphically, yielding a diode voltage (V_D) of 0.9 V and a current (I_D) of 2.0 mA.

PREREQUISITES
  • Understanding of diode I-V characteristics
  • Familiarity with Thevenin's theorem
  • Basic knowledge of circuit analysis
  • Ability to plot graphs and interpret intersections
NEXT STEPS
  • Study the application of Thevenin's theorem in circuit analysis
  • Learn about diode I-V characteristic equations
  • Explore graphical methods for solving circuit problems
  • Investigate numerical methods for circuit analysis using simultaneous equations
USEFUL FOR

Electrical engineers, circuit designers, and students studying semiconductor devices will benefit from this discussion, particularly those looking to deepen their understanding of diode behavior in circuits.

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can anybody pls show me how to determine numerically the diode current
I(D) for t<0 and t>0

thanx
 
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First of all, there is NO given time-dependent information. Why do you want I(D) for t<0 and t>0? I assume you want the I(D) for the diode's working point.

It would be better understood if we plug in some values. Here we go:

Diode1.jpg


Given:

[tex]R_{1}=R_{2}=R_{3}=100\Omega[/tex]

[tex]I_{0}=24\ mA[/tex]


By considering the open (oc) and short circuits (sc), you will obtain two values where:

[tex]I_{oc}=0[/tex] as [tex]V_{oc}=V_{Th}=1.2\ V[/tex]

[tex]I_{sc}=\frac{V_{Th}}{R_{Th}}=8.0\ mA[/tex]


Here is the I-V source characteristic, the red line:

I-V_Characteristic_1A.jpg



Now, if the characteristic of the diode is given by

Diode_Equation1.jpg


Then plotting the characteristic on the same graph gives the green line:

I-V_Characteristic_1B.jpg




A. Graphically
So you know that the intersection is the working point for the diode and there you can write down the value of [tex]V_{D}=0.9\ V[/tex] and [tex]I_{D}=2.0\ mA[/tex].

B. Numerically
Find the equation of the I-V source characteristic using the famous [tex]Y=mX+C[/tex] where you will expect C = 0.008 A and and negative slope m. Then, solving the simultaneous equations proves the values obtained in A. That's simple.
 
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