How to differentiate y = ln( 1+x^2)^1/2

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SUMMARY

The differentiation of the function y = ln(1+x^2)^(1/2) results in the expression x/(1+x^2). To achieve this result, one must apply the power rule and chain rule correctly. The function should be interpreted as ln(√(1+x^2)), which simplifies to (1/2)ln(1+x^2). The constant factor of 1/2 remains outside during differentiation, contrary to the misconception that it disappears.

PREREQUISITES
  • Understanding of differentiation rules, specifically the power rule and chain rule.
  • Familiarity with logarithmic properties and simplification techniques.
  • Basic knowledge of calculus, particularly functions involving natural logarithms.
  • Ability to manipulate algebraic expressions involving square roots.
NEXT STEPS
  • Review the power rule and chain rule in calculus.
  • Study logarithmic differentiation techniques for complex functions.
  • Practice simplifying expressions involving natural logarithms and square roots.
  • Explore additional examples of differentiating composite functions.
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Students studying calculus, particularly those focusing on differentiation techniques, as well as educators looking for examples of logarithmic differentiation.

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Homework Statement



hey guys, got a question. how do you differentiate y=ln(1+x^2)^1/2. any help would be appreciated, thanks

Homework Equations



answer is x/(1+x^2)

The Attempt at a Solution

 
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Power rule and chain rule.
 


To get the answer you have listed your function must be \ln \sqrt{1+x^2} and not \sqrt{\ln(1+x^2)}. You can write \ln \sqrt{1+x^2}=\frac{1}{2}\ln (1+x^2), perhaps this form is less intimidating?
 


so the 1/2 just stays out the front without it being differentiate, i thought it dissapeared? thanks for the replys
 


geffman1 said:
so the 1/2 just stays out the front without it being differentiate, i thought it dissapeared? thanks for the replys
Go check your rules of differentiation again...
 

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