- #1
rwooduk
- 762
- 59
This is the integral: NB everything in the expenential is in a squared bracket, couldn't get tex to do it
[tex]\frac{1}{2\pi}\int_{\infty }^{\infty} e^{\tfrac{q\Delta}{\sqrt{2}}-\tfrac{ix}{\sqrt{2}\Delta}}dq[/tex]
The only information the tutor has given use to solve this is to use substitution and this:
[tex]\int_{\infty }^{\infty} e^{\tfrac{-q^{2}}{2\Delta^{2}}} dq = \sqrt{2 \pi}\Delta[/tex]
Please could someone give me a point int the right direction? If w is the new variable what should i put it equal to?
Thanks for any help!
[tex]\frac{1}{2\pi}\int_{\infty }^{\infty} e^{\tfrac{q\Delta}{\sqrt{2}}-\tfrac{ix}{\sqrt{2}\Delta}}dq[/tex]
The only information the tutor has given use to solve this is to use substitution and this:
[tex]\int_{\infty }^{\infty} e^{\tfrac{-q^{2}}{2\Delta^{2}}} dq = \sqrt{2 \pi}\Delta[/tex]
Please could someone give me a point int the right direction? If w is the new variable what should i put it equal to?
Thanks for any help!