How to Evaluate an Integral of a Vector Field along a Curve?

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SUMMARY

The integral of a vector field along a curve can be evaluated using the formula U = ∫F∙ds, where F is defined as F = (ayz + bx + c)î + (axz + bz)ĵ + (axy + by)k̂. To solve this integral, one must parameterize the curve C between two endpoints P1 and P2, replacing the variables x, y, z with a parameter such as s or θ. The differential ds can be expressed in terms of the chosen parameter, facilitating the evaluation of the integral.

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if i have a function U..

U=∫F∙ds

where F=<ayz+bx+c , axz+bz , axy+by> , a,b,c are constants

so.. F=(ayz+bx+c)[itex]\hat{x}[/itex] + (axz+bz)[itex]\hat{y}[/itex] + (axy+by)[itex]\hat{z}[/itex]

then how do i solve this integral? i have to either replace the x,y,z terms with something in terms of 's' (which is the displacement by the way, ie.. s= [itex]\sqrt{x^2+y^2+z^2}[/itex]
or i have to replace ds with some parametric ..stuff... how do i evaluate something like this?
 
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Hi iScience! :smile:
iScience said:
U=∫F∙ds

or i have to replace ds with some parametric ..stuff... how do i evaluate something like this?

Let's write that out in full …

it's an integral over a curve C between two endpoints P1 and P2: ##U = \int_C \mathbf{F}\cdot d\mathbf{s}##

so yes you have to use some parameter, which may be s itself, or may be something easier to use, eg θ with ds = (-rsinθdθ,rcosθdθ) :wink:
 

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