How to Find a Plane Equation Parallel to Another Plane?

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Homework Help Overview

The discussion revolves around finding the equation of a plane that is parallel to a given plane and passes through a specific point. The subject area is geometry, specifically the properties of planes in three-dimensional space.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the method of finding a plane equation using a point and the normal vector derived from the parallel plane. There is confusion regarding the correct substitution of the point into the plane equation.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on how to approach the equation setup. There is an acknowledgment of the need to ensure the equation passes through the specified point, and multiple interpretations of the approach are being explored.

Contextual Notes

The original poster is required to format the equation equal to zero, and there is uncertainty about the correct method to achieve this while ensuring the equation is valid for the given point.

krtica
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Q: Find an equation of a plane through the point (3, -3, -2) which is parallel to the plane −2x+1y+4z=−6 in which the coefficient of x is -2.

The website asks you to format the answer equal to zero. My input is -2x+y+4z+23, but it shows wrong. I have checked my answer a couple of times, but am not sure how to approach it differently.
 
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Hi krtica! Welcome to PF! :smile:
krtica said:
Q: Find an equation of a plane through the point (3, -3, -2) which is parallel to the plane −2x+1y+4z=−6 in which the coefficient of x is -2.

My input is -2x+y+4z+23 …


That doesn't go through (3, -3, -2). :wink:
 


tiny-tim said:
Hi krtica! Welcome to PF! :smile:



That doesn't go through (3, -3, -2). :wink:

Thanks!

Isn't the equation for a plane a(x-xi)+b(y-yi)+c(z-zi)=0? Where a,b,c are the vector components?
 
Yes, but if you have actual numbers, it's a lot easier to write it as ax + by + cz = …, and just fill in the number so that it fits the given point. :wink:
 
By filling in the numbers, do you mean substituting the point in x,y,z? I am not quite sure exactly what you mean, my apologies.
 
Yes, substituting the point in ax + by + cz …

then it's bound to go through that point, isn't it? :wink:
 
God! Got it.

Thank you, I really do appreciate your help.
 

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