How to find an average acceleration using an average velocity?

AI Thread Summary
To find average acceleration using average velocity, it's essential to have the complete problem statement, as context is crucial for accurate calculations. The average velocity calculated was 1.146788991 m/s over 8.72 seconds, but without knowing the final velocity, the formula a_ave=(Vf-Vi)/(Tf-Ti) cannot be applied. Multiplying average velocity by time does not yield acceleration, as it results in distance. Instead, it may be more appropriate to consider the average velocity as (Vf - Vi)/2 if initial and final velocities are known. Providing the full problem statement will help clarify the necessary calculations for determining average acceleration.
Cacti
Messages
1
Reaction score
2
Homework Statement
Calculate the average acceleration for each member over the first 10.0 m.
Relevant Equations
None given
I calculated the average velocity in a previous problem and got 1.146788991m/s over a time of 8.72s. I know I can’t use a_ave=(Vf-Vi)/(Tf-Ti) because I don’t know the final velocity and have no way to find it. Do I multiply average velocity by time?
 
Physics news on Phys.org
Cacti said:
Homework Statement: Calculate the average acceleration for each member over the first 10.0 m.
Homework Equations: None given

I calculated the average velocity in a previous problem and got 1.146788991m/s over a time of 8.72s. I know I can’t use a_ave=(Vf-Vi)/(Tf-Ti) because I don’t know the final velocity and have no way to find it. Do I multiply average velocity by time?
Please post the full problem so that we can see what data you have available.
 
  • Like
Likes FactChecker
The full problem statement is necessary. For one thing, there is a difference between "average" over time versus "average" over distance.
 
Cacti said:
Do I multiply average velocity by time?
Not if you are looking for something that has dimensions of acceleration.
 
Maybe average velocity= (Vf - Vi)/2?
 
Cacti said:
Homework Statement: Calculate the average acceleration for each member over the first 10.0 m.
Homework Equations: None given

I calculated the average velocity in a previous problem and got 1.146788991m/s over a time of 8.72s. I know I can’t use a_ave=(Vf-Vi)/(Tf-Ti) because I don’t know the final velocity and have no way to find it. Do I multiply average velocity by time?

The rule of the HW forum is that you post the full statement of the problem, not just snippets of it.

Zz.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top