1. Sep 14, 2013 #1

   smantics

   

   Given only an uniform electric field with unit vectors in the x, y, and z directions, how would you go about calculating the electric-charge density distribution p(r) for that electric field?

    

   smantics, Sep 14, 2013
2. 
   Phys.org - latest science and technology news stories on Phys.org

   • • Superconductivity research reveals potential new state of matter
   • • Physicists measure complementary properties using quantum clones
   • • "Fixed-field" accelerator transports multiple particle beams at a wide range of energies through a single beam pipe
3. Sep 14, 2013 #2

   Jolb

   

   One nice formula you might try applying is one of Maxwell's equations: [tex]\nabla \cdot \mathbf{E} = \frac {\rho} {\varepsilon_0}[/tex] The symbol [itex]\rho[/itex] is the charge density that generates the electric field [itex]\mathbf{E}[/itex], and [itex]\varepsilon_0[/itex] is a proportionality constant called the permittivity of free space.

    

   Jolb, Sep 14, 2013
4. Sep 14, 2013 #3

   smantics

   

   Thanks, I will try that.

    

   smantics, Sep 14, 2013
5. Sep 15, 2013 #4

   mikeph

   

   The divergence of a uniform field is zero. There are no charges, at least where the field is uniform.

    

   mikeph, Sep 15, 2013

• Log in with Facebook
• Log in with Twitter

Your name or email address:

Do you already have an account?

• No, create an account now.
• Yes, my password is:
• Forgot your password?

Stay logged in